beliav...@aol.com writes: > yy = list(chain.from_iterable([list(repeat(aa,nrep)) for aa in xx]))
The chain approach seems more natural to me: yy = list(chain.from_iterable(map(lambda x: [x,x], xx))) may make the doubling more obvious, and in Python 3 it should avoid the intermediate lists since map creates a generator. Depending on the usage, you might also not need the outermost list, making yy a lazy generator as well. -- https://mail.python.org/mailman/listinfo/python-list
