just extract b[i][0:1] and b[i][1:2] out of for loop but i depend on for loop
def node(mmm, A, B): H2 = [MM[mmm][A+B] for i in range(len(b))] return H2 node(5, b[i][0:1], b[i][1:2]) it is not convenient to disclose in detail just expect to discuss from the view of programming On Wednesday, June 8, 2016 at 4:56:56 PM UTC+8, Steven D'Aprano wrote: > On Wednesday 08 June 2016 17:31, meInvent bbird wrote: > > > b = [str(i)+str(j)+str(k) for i in range(m) for j in range(m) for k in > > range(m)] > > b[21][0:1]+b[21][1:2] > > b[21][1:2]+b[21][2:3] > > b[21][0:1]+b[21][2:3] > > > > > > originally, > > > > mmm = 5 > > H2 = [MM[mmm][b[i][0:1]+b[i][1:2]] for i in range(len(b))] > > This is a mess. I don't understand what you are trying to do. You have these > variable names that don't mean anything, like "b" and "H2", and others which > aren't defined, like MM. I don't understand what you are trying to > accomplish, > or the purpose of your code. > > > > how to extract b[i][0:1] and b[i][1:2] as parameters? > > I don't understand the question. > > > > def node(mmm, b[i][0:1], b[i][1:2]): > > H2 = [MM[mmm][A+B] for i in range(len(b))] > > return H2 > > > > node(5, b[i][0:1], b[i][1:2]) > > Explain what node() is supposed to do, in English. Don't write any code yet. > What is its purpose? What does it return? What arguments does it need to take > in order to perform its purpose? > > > -- > Steve -- https://mail.python.org/mailman/listinfo/python-list
