Jignesh Sutar wrote:
> Say I have list of data as given in the example code below, I want to find
> all the unique categories (alphabetic letters) and unique IDs (numbers)
> and then produce a summary grid as manually entered in the "results". How
> could I code this?
>
> Many thanks in advance,
> Jignesh
>
>
> data= ["A.1", "A.2", "A.3", "B.1", "C.2", "C.3", "D.4", "E.5", "E.6"]
>
> cols=[]
> rows=[]
> for item in data:
> i=item.split(".")
> if i[0] not in cols: cols.append(i[0])
> if i[1] not in rows: rows.append(i[1])
>
> print cols
> print rows
>
> results=
> [["Row/Col", "A", "B", "C", "D", "E"],
> [1, 1, 1, 0, 0, 0],
> [2, 1, 0, 1, 0, 0],
> [3, 1, 0, 1, 0, 0],
> [4, 0, 0, 0, 1, 0],
> [5, 0, 0, 0, 0, 1],
> [6, 0, 0, 0, 0, 1]]
$ cat pivot_jignesh.py
def add(x, y):
return x + y
def pivot(
data,
accu=add,
default=0, empty=0, origin=""):
rows = {}
columnkeys = set()
for rowkey, columnkey, value in data:
column = rows.setdefault(rowkey, {})
column[columnkey] = accu(column.get(columnkey, default), value)
columnkeys.add(columnkey)
columnkeys = sorted(columnkeys)
result = [
[origin] + columnkeys
]
for rowkey in sorted(rows):
row = rows[rowkey]
result.append([rowkey] + [row.get(ck, empty) for ck in columnkeys])
return result
if __name__ == "__main__":
import pprint
data = ["A.1", "A.2", "A.3", "B.1", "C.2", "C.3", "D.4", "E.5", "E.6"]
data = (item.split(".") for item in data)
data = ((int(row), column, 1) for column, row in data)
pprint.pprint(pivot(data, origin="Row/Col"))
$ python pivot_jignesh.py
[['Row/Col', 'A', 'B', 'C', 'D', 'E'],
[1, 1, 1, 0, 0, 0],
[2, 1, 0, 1, 0, 0],
[3, 1, 0, 1, 0, 0],
[4, 0, 0, 0, 1, 0],
[5, 0, 0, 0, 0, 1],
[6, 0, 0, 0, 0, 1]]
$
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