Bengt Richter wrote:
>>>>[name for dec,name in sorted((int(nm.split('.')[1]),nm) for nm in namelist)]
>
> ['test.1', 'test.2', 'test.3', 'test.4', 'test.10', 'test.15', 'test.20']
Giving a key argument to sorted will make it simpler::
>>> sorted(namelist, key=lambda x:int(x.rsplit('.')[-1]))
-- george
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