Thanks Steve for the clues , quickly tried out # Version 1 doesn't seen
to work.
>>> for line in hostname:
... regex = r'(.*) is array with id {}'.format(devid)
... mo = re.search(regex, line)
... print line, regex, mo
... if mo is not None:
... print mo.group(1)
...
RX-145-1 is array id 1 (.*) is array with id 3 None
RX-145-2 is array id 2 (.*) is array with id 3 None
RX-145-3 is array id 3 (.*) is array with id 3 None
>>> hostname
['RX-145-1 is array id 1', 'RX-145-2 is array id 2', 'RX-145-3 is array id
3']
>>> type(devid)
<type 'int'>
>>> devid
3
---------------------------------------------------------------------------------------------------
>>> devid = '3'
>>> for line in hostname:
... regex = r'(.*) is array with id {}'.format(devid)
... mo = re.search(regex, line)
... print line, regex, mo
... if mo is not None:
... print mo.group(1)
...
RX-145-1 is array id 1 (.*) is array with id 3 None
RX-145-2 is array id 2 (.*) is array with id 3 None
RX-145-3 is array id 3 (.*) is array with id 3 None
>>> type(devid)
<type 'str'>
----------------------------------------------------------------------------------------------
>>> for line in hostname:
... regex = r'(.*) is array with id %d' % (devid)
... mo = re.search(regex, line)
... print line, regex, mo
... if mo is not None:
... print mo.group(1)
...
RX-145-1 is array id 1 (.*) is array with id 3 None
RX-145-2 is array id 2 (.*) is array with id 3 None
RX-145-3 is array id 3 (.*) is array with id 3 None
---------------------------------------------------------------------------------------------------
Looks like Iam missing something ?
Regards,
Ganesh
On Wed, Sep 21, 2016 at 5:57 AM, Steve D'Aprano <steve+pyt...@pearwood.info>
wrote:
> On Wed, 21 Sep 2016 04:04 am, Ganesh Pal wrote:
>
> > I am on python 2.7 and Linux
> >
> > I have the stdout in the below form , I need to write a function to get
> > hostname for the given id.
> >
> >
> > Example:
> >
> >>>> stdout
> > 'hostname-1 is array with id 1\nhostname-2 is array with id
> 2\nhostname-3
> > is array with id 3\n'
> >
> >
> > def get_hostname(id)
> > return id
> >
> > what's a better option here
> >
> > 1. store it in list and grep for id and return
> > 2. store it in dict as key and value i.e hostname = { 'hostname1': 1} and
> > return key
> > 3. any other simple options.
>
>
> Why don't you write a function for each one, and see which is less work?
>
> # Version 1: store the hostname information in a list as strings
>
> hostnames = ['hostname-1 is array with id 1',
> 'hostname-2 is array with id 2',
> 'hostname-842 is array with id 842']
>
> def get_hostname(id):
> for line in hostnames:
> regex = r'(.*) is array with id %d' % id
> mo = re.match(regex, line)
> if mo is not None:
> return mo.group(1)
> raise ValueError('not found')
>
>
> # Version 2: store the hostname information in a dict {hostname: id}
>
> hostnames = {'hostname1': 1, 'hostname2': 2, 'hostname842': 842}
>
> def get_hostname(id):
> for key, value in hostnames.items():
> if value == id:
> return key
> raise ValueError('not found')
>
>
> # Version 3: use a dict the way dicts are meant to be used
>
> hostnames = {1: 'hostname1', 2: 'hostname2', 842: 'hostname842'}
>
> def get_hostname(id):
> return hostnames[id]
>
>
>
>
>
>
>
>
> --
> Steve
> “Cheer up,” they said, “things could be worse.” So I cheered up, and sure
> enough, things got worse.
>
> --
> https://mail.python.org/mailman/listinfo/python-list
>
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