Deborah Swanson wrote: >> >value = getattr(record, label) >> >> That should work. > > We may agree that it *should* work, by an intuitive grasp of how it > should work, but it doesn't. You get "object has no attribute 'label'.
Only if the namedtuple (1) does not have a label attribute and (2) the value of the name label is the string "label" In that case both label = "label" getattr(record, label) and record.label will fail with the same AttributeError. The problem is *not* the dynamic access through getattr(). >> Indeed you cannot change the namedtuple's attributes. Like the "normal" >> tuple it is designed to be immutable. If you want changes in one list >> (the group) to appear in another (the original records) you need a >> mutable data type. > > Sadly, that does seem to be the correct conclusion here. Think hard if you really need the original list. -- https://mail.python.org/mailman/listinfo/python-list
