On Monday, June 12, 2017 at 7:33:03 PM UTC+1, José Manuel Suárez Sierra wrote: > Hello, > I am stuck with a (perhaps) easy problem, I hope someone can help me: > > My problem is: > I have a list of lists like this one: > [[55, 56, 57, 58, 83, 84, 85, 86, 89, 90, 91, 92, 107, 108, 109, 110, 111, > 117, 118, 119, 120, 128, 129, 130, 131, 135, 136, 137, 138, 184, 185, 186, > 187, 216, 217, 218, 219, 232, 233, 234, 235, 236, 237, 238, 267, 268, 269, > 270, 272, 273, 274, 275], [2, 3, 4, 5, 9, 10, 11, 12, 21, 22, 23, 24, 29, 30, > 31, 32, 56, 57, 58, 59, 65, 66, 67, 68, 74, 75, 76, 77, 78, 89, 90, 91, 92, > 98, 99, 100, 101, 102, 125, 126, 127, 128, 131, 132, 133, 134, 135]] > > And what I want is to store some of these datum into another list according > to the next conditions: > 1. I just want to store data if these values are consecutive (four in four), > for instance, for first element I would like to store into the new list: > [[[55,58],[83,86],....[n,n+3]]] and so on. > I tried something like this: > > x=0 > y=0 > while list6[x][y] == list6[x][y+1]-1 and list6[x][y] == > list6[x][y+1]-2 and list6[x][y] == list6[x][y+1]-3 or list6[x][0]: > > list7.append(list6[x][y]) > list7.append(list6[x][y+3]) > y = y+1 > if (list6[x][y])%(list6[x][len(list6[x])-1]) == 0: > x= x+1 > > if len(list6[x]) == x and len(list6[x][y]) == y: > break > > > It does not work > > I appreciate your help > Thank you
Perhaps use the recipe for consecutive numbers from here https://docs.python.org/2.6/library/itertools.html#examples It will have to be modified for Python 3, I'll leave that as an exercise. Kindest regards. Mark Lawrence. -- https://mail.python.org/mailman/listinfo/python-list
