"Steven D'Aprano" <steve+comp.lang.pyt...@pearwood.info> a écrit dans le message de
news:597841eb$0$2878$c3e8da3$76491...@news.astraweb.com...
On Wed, 26 Jul 2017 08:58:03 +0200, ast wrote:
Hello
random.choice on a set doesn't work because sets are not indexable
so I found nothing better than taking an element and puting it back
a = {5, 7, 8, 3, 0, 8, 1, 15, 16, 34, 765443}
elt = a.pop()
a.add(elt)
That's not *random*, it is arbitrary but predictable. If you try it twice
in a row, you will probably get the same element each time. (Depends on
the elements, but very likely.)
If you need a random element, best way is:
random.choice(list(a))
8
random.choice(list(a))
15
random.choice(list(a))
16
Thanks
random.sample(a, 1)[0] works too
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