On 2017-11-19 19:03, Ben Finney wrote:
Cheri Castro <blueyes7...@gmail.com> writes:
I've tried several variations but haven't been able to figure out why
my final if elif statement won't print.
The code you presented here does not have any ‘elif’ clause. Did you
mean to show different code?
I tried using return, I tried using 1's and 0's rather than yes and
no. Not sure what the issue is. Please, help.
Your questions are welcome here, but you may also be interested in
<URL:http://mail.python.org/mailman/listinfo/tutor> the “tutor”
discussion forum especially for Python beginners.
#This function will print how many yes answers the user has and a message
def correctAnswers(job, house, yard, time):
if correctAnswers == 'yes':
print ("Congratulations! You should get a puppy!")
else:
return "I'm sorry, you shouldn't get a puppy."
The ‘if’ clause tests the value of ‘correctAnswers’. Where do you expect
that value to come from? Nothing in the function ever sets a value to
that name.
On the other hand, the function never makes use of ‘job’, ‘house’,
‘yard’, or ‘time’. Why are those parameters to the function?
The function itself is called 'correctAnswers', and a function is never
equal to a string.
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