On 2018-05-24 00:57, asa32s...@gmail.com wrote:
i want to check/return for 3 conditions, it loops shortest str and finds diff
in other
1. if difference is immediate before end of range, return index, exit
2. if string length is same and index loop is done, return 'identical'
3. if neither of above is found. it means the short loop ended and every letter
was same so next letter of longer str is the diff, just return idex+1
but my last print statement always print. not sure how to end this
[code]
str1= "kitti cat"
str2= 'kitti catt'
lenStr1= len(str1)
lenStr2= len(str2)
#find shortest str and loop range with this one
if lenStr1 >= lenStr2:
str= str2
else:
str= str1
# loop each character of shortest string, compare to same index of longer string
# if any difference, exit and return index of difference
for idx in range(len(str)):
a= str1[idx]
b= str2[idx]
if a != b: #immeditely exit, since non-match found
print(idx)
break
else:
if len(str1) == len(str2) and idx == len(str1)-1: #if no difference
print 'identical'
print("identical")
break
print(idx+1)
[/code]
The 'for' loop (and also the 'while' loop) can have an 'else' clause,
which is run if it didn't break out of the loop:
for idx in range(len(str)):
# body of loop
...
else:
# didn't break out of the loop
print(idx+1)
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