On 03/07/2018 07:12, Gregory Ewing wrote:
import signal, sys
def timeout(*args):
print("Too late!")
sys.exit(0)
signal.signal(signal.SIGALRM, timeout)
signal.setitimer(signal.ITIMER_REAL, 15)
data = input("Enter something: ")
print("You entered: ", data)
This doesn't work in windows (SIGALRM not available see
https://stackoverflow.com/questions/6947065/right-way-to-run-some-code-with-timeout-in-python)
For completeness I think it needs the handler restoring; this seemed to work for me in linux; I did try using SIG_DFL, but
apparently that just prints 'Alarm clock' and exits at least
import signal, sys, time
def timeout(*args):
print("Too late!")
sys.exit(0)
signal.signal(signal.SIGALRM, timeout)
signal.setitimer(signal.ITIMER_REAL, 15)
data = input("Enter something: ")
signal.signal(signal.SIGALRM,signal.SIG_IGN)
print("You entered: ", data)
for i in reversed(xrange(15)):
print i
time.sleep(1)
print 'finished!'
if I leave out the signal.signal(signal.SIGALRM,signal.SIG_IGN) then the
timeout function gets called anyway.
--
Robin Becker
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