> Can you tell me how this works?
"results[0]" returns a list with two elements. Let's call it "pair"
pair = results[0]
# ['1', 0.99921393753233001]
Now, we can use regular sequence unpacking to retrieve first and second
argument:
a, b = pair
which is equivalent to this:
a = pair[0]
b = pair[1]
If you're not sure how many items you have in a list, you can use an asterisk
operator:
li = [1, 2, 3, 4]
a, b, *c = li
which is equivalent to:
a = li[0]
b = li[1]
c = li[2:]
Iwo Herka
https://github.com/IwoHerka
‐‐‐‐‐‐‐ Original Message ‐‐‐‐‐‐‐
On 22 July 2018 12:40 PM, Sharan Basappa <sharan.basa...@gmail.com> wrote:
>
>
> Thanks. This works in my example. Can you tell me how this works?
>
> > You can simply unpack the inner list:
> >
> > a, b = results[0]
> >
> >
> > Iwo Herka
> >
> > ‐‐‐‐‐‐‐ Original Message ‐‐‐‐‐‐‐
> >
> > On 22 July 2018 11:47 AM, Sharan Basappa sharan.basa...@gmail.com wrote:
> >
> > > I am using a third party module that is returning list of lists.
> > >
> > > I am using the example below to illustrate.
> > >
> > > 1 results = [['1', 0.99921393753233001]]
> > >
> > > 2 k = results[0]
> > >
> > > 3 print k[0]
> > >
> > > 4 print k[1]
> > >
> > > Assume the line 1 is what is returned.
> > >
> > > I am assigning that to another list (k on line 2) and then accessing the
> > > 1st and 2nd element in the list (line 3 and 4).
> > >
> > > How can I access elements of 1 and 0.99 without assigning it to another
> > > list?
> > >
> > > https://mail.python.org/mailman/listinfo/python-list
>
> Thanks
>
>
> ----------
>
> https://mail.python.org/mailman/listinfo/python-list
--
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