Eko palypse wrote:
> No, I have to correct myself
>
> x = 5
> def f1():
> exec("x = x + 1; print('f1 in:', x)")
> return x
> print('f1 out', f1())
>
> results in the same, for me confusing, results.
>
> f1 in: 6
> f1 out 5
Inside a function exec assignments go to a *copy* of the local namespace.
Also LOAD_NAME is used to look up names. Therefore you can read and then
shade a global name with its local namesake.
Inside a function the namespace is determined statically. As f1() has no
assignment to x (code inside exec(...) is not considered) x is looked up in
directly the global namespace using LOAD_GLOBAL.
If you want to access the local namespace used by exec() you have to provide
one explicitly:
>>> x = 5
>>> def f():
... ns = {}
... exec("x += 1", globals(), ns)
... return ns["x"]
...
>>> f()
6
>>> x
5
By the way, in Python 2 where exec was a statement the local namespace is
shared:
>>> x = 5
>>> def f():
... exec "x += 1"
... return x
...
>>> f()
6
>>> x
5
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