Bengt Richter wrote: [it.next() appears to be a noop in the interactive interpreter]
> I guess it could be in the read-eval-print loop Indeed: >>> for i in range(5): ... 42 ... 42 42 42 42 42 Whereas: >>> for i in range(5): ... None >>> Every line with an expression that doesn't evaluate to None is echoed. Therefore it.next() and print it.next() look the same when repr(it.next()) == str(it.next()). No bug :-) Peter -- http://mail.python.org/mailman/listinfo/python-list
