dcwhat...@gmail.com wrote:
> Hi,
>
> I've tried urllib, requests, and some other options. But I haven't found
> a way to trap certain urls that aren't possible to connect from, outside
> the office. In those cases, I need to just output an error.
>
>
> So, the following code will cover the 404s and similar errors for most of
> the problem IPs and urls. But for these particular problem urls, while
> debugging it keeps transferring control to adapters.py, and outputting
>
> requests.exceptions.ConnectionError:
> HTTPSConnectionPool(host='xxxxxxx.state.gov', port=443): Max retries
> exceeded with url: /xxx/xxx/xxx....(Caused by
> NewConnectionError('<urllib3.connection.VerifiedHTTPSConnection
> object at 0x03934538>: Failed to establish a new connection: [Errno
> 11001] getaddrinfo failed'))
>
>
> How do I trap this error, without invoking adapters.py?
If requests catches the error -- I don't know.
If you fail to catch the error in your code -- what happens if you use a
bare except? Like
try:
... # your code
except:
print(sys.exc_info())
This should print the type of exception you need to catch.
> I've tried many things, but the most recent is this code, from the web:
>
>
>
> try:
> r = requests.get(url,timeout=3)
> r.raise_for_status()
> except requests.exceptions.HTTPError as errh:
> print ("Http Error:",errh)
> except requests.exceptions.ConnectionError as errc:
> print ("Error Connecting:",errc)
> except requests.exceptions.Timeout as errt:
> print ("Timeout Error:",errt)
> except requests.exceptions.RequestException as err:
> print ("OOps: Something Else",err)
>
>
> It seems like the error should be trapped by the exception above
> requests.exceptions.ConnectionError, but instead its' hitting adapters.py.
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