On 2021-01-13, Bischoop <bisch...@vimart.net> wrote:
I know what was wrong:
> m = s.index(i)
I forgot that m will return first index of i.
So tried that way but still getting out of index although I that that
I'm making sure not to get out of index.
s = 'aabskaaabadcccch'
c = 0
t = list(set(s)) # list of characters in s
li=[0,0,0,0,0,0] # list for counted repeats
print(t)
for x in t:
h = t.index(x)
for index, i in enumerate(s):
maximus = len(s)
if i == x:
c += 1
if index < maximus:
if s[index +1] != x: # if next element is not x
if c > li[h]: #update c if bigger than existing
li[h] = c
c = 0
else:
if c > li[h]:
li[h] = c
for i in t:
n = t.index(i)
print(i,li[n])
print(f'{s[li.index(max(li))]} appears {max(li)} consecutive times')
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