Richard Damon <rich...@damon-family.org> writes: > On 8/26/21 6:01 AM, Loris Bennett wrote: >> Hi, >> >> When using configargparse, it seems that if a value is to be read from a >> config file, it also has to be defined as a command-line argument in >> order to turn up as an attribute in the parser namespace. >> >> I can sort of see why this is the case, but there are also some options >> I would like to read just from the config file and not have them >> available as command-line options. This would be, say, to prevent the >> number of options on the command-line from becoming bloated by >> little-used settings. >> >> Is there an elegant way to do this? >> >> Cheers, >> >> Loris >> > Look at the read() member function to supply the file name to read. Then > in the config object there will be sections for each section in the > config file. No need for any of these to be 'options'
Do you have a link for this? As far as I can see, the config files are given in the following manner: p = configargparse.ArgParser(default_config_files=['/etc/app/conf.d/*.conf', '~/.my_settings']) I can obviously just read the config file with configparser, but the idea of configargparse is that an option can be specified as an option, in a config file, or as an environment variable, As far as I can tell, configargparse only loads entries from the config file into the appropriate namespace if they have also been defined as long options (i.e. with '--'). I was hoping to access *all* the config file entries, regardless of whether they are also options, since the config is obviously being read. Cheers, Loris -- This signature is currently under construction. -- https://mail.python.org/mailman/listinfo/python-list