What Dennis Lee is saying I will see to it later. Right now what mrabarrnett is saying is of use.
Why does the code written below is not giving any output? xls = ExcelFile('ABC.xlsx') df = xls.parse(xls.sheet_names[0], index_col=1) x=df.to_dict() print (x) Only the contents of the first column and the column number is required in the dictionary -- https://mail.python.org/mailman/listinfo/python-list