On 20/01/22 12:09 am, Chris Angelico wrote:
At this point, the refcount has indeed been increased.return self; }And then you say "my return value is this object". So you're incrementing the refcount, then returning it without incrementing the refcount. Your code is actually equivalent to "return self".
Chris, you're not making any sense. This is C code, so there's no way that "return x" can change the reference count of x. > The normal thing to do is to add a reference to whatever you're > returning. For instance, Py_RETURN_NONE will incref None and then > return it. > The OP understands that this is not a normal thing to do. He's trying to deliberately leak a reference for the purpose of diagnosing a problem. It would be interesting to see what the actual refcount is after calling this function. -- Greg -- https://mail.python.org/mailman/listinfo/python-list
