Here's how my code does it:
import calendar def add_months(value: date, n: int): """Return a date value with n months added (or subtracted if negative).""" year = value.year + (value.month - 1 + n) // 12 month = (value.month - 1 + n) % 12 + 1 day = min(value.day, calendar.monthrange(year, month)[1]) return date(year, month, day) Paul On Tue, 2022-06-21 at 05:29 +0100, Paulo da Silva wrote: > Hi! > > I implemented a part of a script to subtract n months from datetime. > Basically I subtracted n%12 from year and n//12 from the month adding > 12 > months when it goes<=0. Then used try when converting to datetime > again. > So, if the day is for example 31 for a 30 days month it raises a > ValuError exception. Then I subtract 1 to day and repeat. > > The code seems too naive and very very complicated! > What is the best way to achieve this? Any existent module? > > At the very end, what I want is to subtract nx where x can be y, m, > w, d > for respectively years, months, weeks or days. > > I feel I am missing something here ... > > Thanks. > Paulo > -- https://mail.python.org/mailman/listinfo/python-list
