It is not very important, but I am just curious. Original I had in a program: values = [*range(100)]
But because it is done quite often I expected that initialising: range_list = [*range(100)] and then use: values = range_list.copy() Would be more efficient. So I tried: timeit('values = [*range(100)]') 1.6964535564184189 and: timeit('new_values = values.copy()', 'values = [*range(100)]') 0.6457642465829849 That showed that it should make a positive difference. But when changing the program it took a little bit more time. I find the code with the copy a little bit better, so I kept it. But I am curious why the effect is the opposite of what I expected. It does not hurt to understand optimisation better, so I can do a better job when I need it. -- Cecil Westerhof Senior Software Engineer LinkedIn: http://www.linkedin.com/in/cecilwesterhof -- https://mail.python.org/mailman/listinfo/python-list