On 2022-12-07 02:23, Jach Feng wrote:
s0 = r'\x0a' At this moment it was done bydef to1byte(matchobj): ....return chr(int('0x' + matchobj.group(1), 16)) s1 = re.sub(r'\\x([0-9a-fA-F]{2})', to1byte, s0) But, is it that difficult on doing this simple thing?
You could try this:
>>> s0 = r'\x0a'
>>> ast.literal_eval('"%s"' % s0)
'\n'
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