Jach Feng 在 2022年12月7日 星期三上午10:23:20 [UTC+8] 的信中寫道：
> s0 = r'\x0a'
> At this moment it was done by
>
> def to1byte(matchobj):
> ....return chr(int('0x' + matchobj.group(1), 16))
> s1 = re.sub(r'\\x([0-9a-fA-F]{2})', to1byte, s0)
>
> But, is it that difficult on doing this simple thing?
>
> --Jach
I find another answer on the web.
>>> s0 = r'\x0a'
>>> s0.encode('Latin-1').decode('unicode-escape')
'\n'
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