On 5/8/2025 2:05 AM, Left Right via Python-list wrote:
Also, it appears that the change linked above is a lie:
https://docs.python.org/3/reference/lexical_analysis.html#grammar-token-python-grammar-longstringitem
According to the grammar, any character can follow backslash in a
valid Python program. The warning / error raised by this code should
not be a syntax error / warning because the syntax is correct.
"Changed in version 3.12: Unrecognized escape sequences produce a
SyntaxWarning. In a future Python version they will be eventually a
SyntaxError."
See https://docs.python.org/3/reference/lexical_analysis.html#strings
Test case for "\" in triple-quoted string:
[code]
def f():
... """\hello"""
<stdin>:2: SyntaxWarning: invalid escape sequence '\h'
... print('hi')
...
f()
hi
[/code]
This example fits the documentation exactly. A SyntaxWarning is emitted
for the unrecognized escape sequence "\h". The program runs as intended.
Please let's drop all the OT back-and-forth.
On Thu, May 8, 2025 at 7:54 AM Left Right <olegsivo...@gmail.com> wrote:
I think it could be this:
A backslash-character pair that is not a valid escape sequence now
generates a SyntaxWarning, instead of DeprecationWarning. For example,
re.compile("\d+\.\d+") now emits a SyntaxWarning ("\d" is an invalid
escape sequence, use raw strings for regular expression:
re.compile(r"\d+\.\d+")). In a future Python version, SyntaxError will
eventually be raised, instead of SyntaxWarning. (Contributed by Victor
Stinner in gh-98401.)
Found in:
https://docs.python.org/3/whatsnew/3.12.html#other-language-changes
It's not supposed to crash your program though. If the program crashes
because of it, it's a bug in Python.
On Thu, May 8, 2025 at 7:00 AM Bob van der Poel via Python-list
<python-list@python.org> wrote:
Did something change in python buggering up my use of a "\ " sequence in a
triple quoted string?
I have yet to go through my archive on the program, but I tried to run it
today and it crashed quite spectacularly when it hit a """ .... """ line
being used as a comment at the top of a function. I changed the "\" to a
"/" and all is well now.
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