Apparently, calling bind() with a zero "port" will choose some available port number, as demonstrated by this program:
import socket s = socket.socket(socket.AF_INET, socket.SOCK_STREAM) s.bind(("", 0)) print s.getsockname() Here's how it behaved over several runs: $ python soc.py ('0.0.0.0', 34205) $ python soc.py ('0.0.0.0', 34206) $ python soc.py ('0.0.0.0', 34207) I don't know for sure whether this is standard behavior for sockets, or whether it's a special behavior of linux. Jeff
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