Neal Becker wrote: > I can do this with a generator: > > def integers(): > x = 1 > while (True): > yield x > x += 1 > > for i in integers(): > > Is there a more elegant/concise way? >
import itertools
for i in itertools.count():
print i
Will McGugan
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"".join({'*':'@','^':'.'}.get(c,0) or chr(97+(ord(c)-84)%26) for c in
"jvyy*jvyyzpthtna^pbz")
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