"Chris F.A. Johnson" <[EMAIL PROTECTED]> writes:
> On 2005-10-15, Jari Aalto wrote:
> Don't indent:
>
> function compile ()
> {
> python -c '
> import os, sys, py_compile;
> i = 0;
> for arg in sys.argv:
> file = os.path.basename(arg);
> dir = os.path.dirname(arg);
> i += 1;
> if i > 1 and os.path.exists(dir):
> os.chdir(dir);
> print "compiling %s\n" % (file);
> py_compile.compile(file);
> ' $*
> }
Thanks, is there equivalent to this Perl statement in Python?
@list = @ARGV[1 .. @ARGV];
or something similar so that I could avoid the 1 > 1 (sys.argv) check
altogether?
Jari
--
http://mail.python.org/mailman/listinfo/python-list
