this has to be a very silly thing. I have a function foo taking a dictionary as parameters. i.e.: def foo(**kwargs): pass when I call foo(param1='blah',param2='bleh',param3='blih') everything is fine. but when I do: >>> def foo(**kwargs): ... pass ... >>> d=dict(param1='blah',param2='bleh',param3='blih') >>> foo(d)
I get: Traceback (most recent call last): File "<stdin>", line 1, in ? TypeError: foo() takes exactly 0 arguments (1 given) Why? how do I pass the dictionary *d* to foo()? Thanks, - Josh. -- http://mail.python.org/mailman/listinfo/python-list
