> # ok, both methods work and give the expected results
> # so i presume they are different methods.
>
>>>>id(a.m1)
>
> 9202984
>
>>>>id(a.m2)
>
> 9202984
>
>>>>id(a.m1)==id(a.m2)
>
> True
> # Huh? They seem to be the same.
What you observe is rooted in two things:
- python objects bound methods are created on demand. Consider this
example:
class Foo:
def m(self):
pass
f = Foo()
m1 = f.m
m2 = f.m
print id(m1), id(m2)
The reason is that the method iteself is bound to the instance - this
creates a bound method each time.
The other thing is that this bound method instances are immediaty
garbage collected when you don't keep a reference. That results in the
same address being used for subsequent bound method instantiations:
print id(f.m)
print id(f.m)
results in the same id being printed. It doesn't matter if you use m1,
m2 instead, as in your example.
HTH,
Diez
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