hey kent thanks for your help.
so i ended up using a loop but find that i end up getting the same set
of results every time. the code is here:
for incident in bs('tr'):
data2 = []
for incident in bs('h2', {'id' : 'dealName'}):
product2 = ""
for oText in incident.fetchText( oRE):
product2 += oText.strip() + ';'
for incident in bs('a', {'name' : 'D0L3'}):
store2 = ""
for oText in incident.fetchText( oRE):
store2 += oText.strip() + ';'
for incident in bs('a', {'class' : 'nojs'}):
price2 = ""
for oText in incident.fetchText( oRE):
price2 += oText.strip() + ';'
tuple2 = (product2, store2, price2)
data2.append(tuple2)
print data2
and i end up getting the following instead of unique results
pizza, pizzahut, 3.94
pizza, pizzahut, 3.94
pizza, pizzahut, 3.94
pizza, pizzahut, 3.94
>
> I would use a loop that finds the row for a single item with something like
> for item in bs('tr', {'class' : 'base'}):
>
> then inside the loop fetch the values for store, food and price for that
> item and write them to your output file.
>
> Kent
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