[Sergey] | I try to open file with pathname length 282 bytes: | E:\files\..................\something.dat
| [... MS advise ...] just add prefix \\?\ to file name. | But when I try to pass prefixed name to file(), I get the | same result as when I don't add the prefix: file not found. With a file called c:\temp\test.txt, I successfully opened and read it like this: print open (r"\\?\C:\temp\test.txt").read () So the basic functionality works. I didn't artificially generate a long path to see if there's a problem in that direction. But note that r prefix to the string. Is it possible that your string didn't include it? If not, then the backslash character which Windows uses as a separator can be stolen by Python which sees it as an escaping character. TJG ________________________________________________________________________ This e-mail has been scanned for all viruses by Star. The service is powered by MessageLabs. For more information on a proactive anti-virus service working around the clock, around the globe, visit: http://www.star.net.uk ________________________________________________________________________ -- http://mail.python.org/mailman/listinfo/python-list
