Quoting Derek Basch <[EMAIL PROTECTED]>: > Given a value (x) that is within the range (1e-1, 1e7) how do I round > (x) up to the closest exact logarithmic decade? For instance:
How about this:
def roundup(x):
if x < 1:
return 1
else:
return '1' + ('0' * len(str(int(x))))
Jack Orenstein
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