Re: "pow" (power) function

[Paul Rubin]

Schüle Daniel <[EMAIL PROTECTED]> writes:
>  >>> timeit.Timer("111**0.3").timeit()
> 2.3824679851531982
>  >>> timeit.Timer("pow(111,0.3)").timeit()
> 4.2945041656494141
> 
> interesting result
> seems that ** computates faster

Maybe "111**0.3" parses faster than pow(111,0.3), if timeit uses eval.
Also, pow() may incur more subroutine call overhead--better check
the bytecode for both versions.
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