bruno at modulix wrote:
> Lonnie Princehouse wrote:
>
>>>What's your use case exactly ?
>>
>>
>>I'm trying to use a function to implicitly update a dictionary.
>
>
> I think this was pretty obvious. What I wonder is *why* you want/think
> you need to do such a thing -I don't mean there can't be no good reason
> to do so, but this has to be a pretty uncommon use case, and some of the
> gurus here may point you to (possibly other and possibly better)
> solutions if you give a bit more context.
>
> And BTW, please, lauch your python shell and type 'import this', then
> read carefully.
>
>
>
>>The
>>whole point is to avoid the normal dictionary semantics,
>
>
> Yes, but *why ?*
>
>
Well, one way would be:
def f(d, ...):
...
d.update(locals())
Seems to work, though it does create a self-reference in the dictionary
because the dictionary is passed as an argument.
>>> def f(d, a, b, c=23.0):
... print "a:", a, "b:", b, "c:", c
... d.update(locals())
...
>>> myd = {'a': "this is a", 'x': "this is x"}
>>> f(myd, 1, 2, 3)
a: 1 b: 2 c: 3
>>> myd
{'a': 1, 'c': 3, 'b': 2, 'd': {...}, 'x': 'this is x'}
>>>
I can't think of a way to wrap this up as a decorator, though.
regards
Steve
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