[EMAIL PROTECTED] wrote: > John Salerno wrote: >> John Salerno wrote: >>> [EMAIL PROTECTED] wrote: >>> >>>> No. First of all, combining them with the & operator would be >>>> the asnswer to having all four lamps lit in the same position. >>>> But you want exactly 3 (in any combination). The correct way >>>> to combine the switches (using my answer of a[7] b[2] c[5] d[3]) >>>> is to use the boolean expression I gave you initially: >>> Ah, that makes sense. I think I have a handle on it now. Of course, you >>> did the grunt work of making the hex list, which might not have been so >>> fun, but now I can work on using it to get the solution. Once I do, I'd >>> love to compare my answer to yours, because something tells me yours >>> will be much more elegant. :) >> p.s. is there an xor operator in python? > > Yep. The XOR operator is ^. That's why you have to use ** > for exponentiation. In addition to &=AND, there is also > |=OR. I actually gave two boolean expressions. > > First, using the standard notation, where concatenation implies > AND, + is OR and x is XOR (actually, the standard notation > for XOR is a + inside a circle, but my keyboard doesn't have > one of those). > > Y = CD(A x B) + AB(C x D) > > Second, using the Python operators > > Y = ((C & D) & (A ^ B)) | ((A & B) & (C ^ D)) >
Thanks! Back to work for me! :) -- http://mail.python.org/mailman/listinfo/python-list
