> If it weren't for the current CPython optimization (caching small > integers)
This has already been covered elsewhere in this thread. Read up on it. > this code which it appears you would support writing > > if (flags & os.R_OK) is os.R_OK: I do not. You compare a module.CONSTANT to the result of an expression (flags & os.R_OK). Expressions are not names bound to objects, the identity of which is what I'm talking about. This example does not apply. Also, the identity check in my example has a value equality fallback. Yours doesn't, so it really does not apply. > (I think you should give it up... you're trying to push a rope.) I'm not pushing anything. I just don't like being misquoted. Cheers, Joel Hedlund -- http://mail.python.org/mailman/listinfo/python-list
