John Salerno wrote: > But would findall return this match: aMNHiRFLoDLFb ?? > > There are actually two matches there, but they overlap. So how would > your write an RE that catches them both?
I remembered the 'non-consuming' match (?+...) and a miniute of
experimentation gave
the following.
>>> import re
>>> s ="aMNHiRFLoDLFb"
>>> re.findall(r'[A-Z]{3}([a-z])(?=[A-Z]{3})', s)
['i', 'o']
>>>
- Paddy.
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