"Frank Millman" <[EMAIL PROTECTED]> writes: > Interesting. My results are opposite.
I got the same here (cPython 2.4.1): [EMAIL PROTECTED] ~ % python -mtimeit -s "data=[range(100)]*100; row = []" "row[:] = data[23]" 1000000 loops, best of 3: 1.15 usec per loop [EMAIL PROTECTED] ~ % python -mtimeit -s "data=[range(100)]*100" "row = data[23][:]" 100000 loops, best of 3: 1.42 usec per loop [EMAIL PROTECTED] ~ % python -mtimeit -s "data=[range(100)]*100" "row = list(data[23])" 100000 loops, best of 3: 1.93 usec per loop [EMAIL PROTECTED] ~ % > If they are all equivalent from a functional point of view, I lean > towards the second version. I agree with Rune that the third one is > nicer to read, but somehow the [:] syntax makes it a bit more obvious > what is going on. I prefer the third option for readability. It makes it clear that I'll get a *new* list with the 23rd row of data. Just think: how would you get the 1st column of the 23rd row? >>> a = [[1, 2], [2, 3], [3, 4], [4, 5], [5, 6]] >>> a [[1, 2], [2, 3], [3, 4], [4, 5], [5, 6]] >>> a[1] [2, 3] >>> a[1][1] 3 >>> a[1][:] [2, 3] >>> Someone might think that the "[:]" means "all columns" and the syntax to be equivalent to "data[23]". -- Jorge Godoy <[EMAIL PROTECTED]> "Quidquid latine dictum sit, altum sonatur." - Qualquer coisa dita em latim soa profundo. - Anything said in Latin sounds smart. -- http://mail.python.org/mailman/listinfo/python-list
