generators challenge
--------------------
define "limit" and "itially"
so that
limit(foo(x) for x in itially(bar))
works out the same as
limit2(foo,bar)
with
def limit2(foo,bar) :
bar1 = foo(bar)
while bar != bar1 :
bar1,bar = foo(bar),bar1
return bar
Note : be careful with your choice of foo and bar, to prevent infinite
loops when the iterated value won't converge.
To think of it, perhaps "abs(bar-bar1)>epsilon" would be more
appropriate than "bar != bar1" in the above loop - I can imagine
roundoff errors leading to tiny oscillations in the least significant
bits of an otherwise convergent computation.
Best, az
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