Panos Laganakos <[EMAIL PROTECTED]> wrote:
> Is there some other practice than reading all the strings and slicing
> them later?
>
> They're stored in the form of:
> List Group[10]:
> char[17] name;
>
> So I thought of doing:
> unpacked = unpack('%s' % (10*17), data)
>
> And then slicing the list by a step of 17.
>
> Is there some way to have unpack return a tuple with each element
> holding the name (char[17])?
unpack by formatstring 10*'17s' ...
Alex
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