alf wrote:
> Hi,
>
> Would it be .append()? Does it reallocate te list with each apend?
>
> l=[]
> for i in xrange(n):
> l.append(i)
>
<dumb>
FWIW, you'd have the same result with:
l = range(n)
</dumb>
More seriously (and in addition to other anwsers): you can also
construct a list in one path:
l = [i for i in xrange(n)]
or if you want operations and conditionals :
l = [trasform(i) for i in xrange(n) if match_some_cond(i)]
HTH
--
bruno desthuilliers
python -c "print '@'.join(['.'.join([w[::-1] for w in p.split('.')]) for
p in '[EMAIL PROTECTED]'.split('@')])"
--
http://mail.python.org/mailman/listinfo/python-list
