godavemon wrote:
> I need to take floats and dump out their 4 byte hex representation.
> This is easy with ints with the built in hex function or even better
> for my purpose
>
> def hex( number, size ):
> s = "%"+str(size) + "X"
> return (s % number).replace(' ', '0')
This should be a trifle nicer:
def hexx(number, size): # don't shadow the "hex" builtin
s = "%0s" + str(size) + "X"
return s % number
> but I haven't been able to find anything for floats. Any help would be
> great.
Getting to float bytes is tougher.
First, python Floats are C Doubles, so you probably mean 8=byte hex.
import array
def eights(number, swap=False):
data = array.array('d', [number])
if swap:
data.byteswap()
return ' '.join(hexx(ord(char), 2) for char in data.tostring())
def fours(number, swap=False):
data = array.array('f', [number])
if swap:
data.byteswap()
return ' '.join(hexx(ord(char), 2) for char in data.tostring())
--Scott David Daniels
[EMAIL PROTECTED]
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