placid wrote: > i did try it in a Python shell after i learnt what it was. Like i said > *args will be a list, but when i try **args with the following code it > doesnt work > > def test(**args): > keys = args.keys() > for key in keys: > print key+"="+args(key) >
When you post here, it helps if instead of saying 'it doesnt work' you say what you expected to happen and what actually happened (and quote exact error messages, dont paraphrase them). If I try your code it works fine: it defines a function. If I try to call your function, even though you didn't include a call in what 'doesnt work', then I get the exception I would expect, namely that you are trying to call args as though it were a function 'args(key)' instead of subscripting it as a dictionary 'args[key]'. Fixing that will then generate a different error, but I'm sure you'll be able to figure it out. -- http://mail.python.org/mailman/listinfo/python-list
