Re: Unbound Local error? How?

[Hari Sekhon]

Bruno Desthuilliers wrote: Hari Sekhon wrote: I've got some code as follows: import re re_regexname = re.compile('abc') ..... ..... various function defs ..... def func1(): ... func2() ... def func2(): if re_regexname.match('abc'): <do something> if __name__ == '__main__': func1() but this returns the Traceback: UnboundLocalError: local variable 're_regexname' referenced before assignment this is *not* the traceback. This is only the error message. The traceback contains all needed informations (or at least all possible information at this point) to know what happened. But you did not post the traceback. Nor did you post the minimal runnable code snippet producing this error. How? How could we know ? sorry, I know it looks like I was being stingy but the traceback was not that helpful, not without seeing more a huge amount more of the code. I was trying to abbreviate. Traceback (most recent call last):   File "./backup.py", line 649, in ?     backup(machine,share)   File "./backup.py", line 364, in backup     backupdir(source,destination)   File "./backup.py", line 398, in backupdir     (dirlist,filelist) = getdirlisting( source )   File "./backup.py", line 445, in getdirlisting     if re_skip_dirs.match(x): UnboundLocalError: local variable 're_skip_dirs' referenced before assignment This doesn't really show that much, I figured the problem was the following: def getdirlisting():      re_skip_dirs = re_skip_top_dirs   #Here's the culprit where both these regex compiled objects were declared at the top level, it seems that the assignment is trying to use the local variable re_skip_top_dirs which doesn't exist, that's why I'm getting a traceback, commenting out this line it runs fine. -h

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