Pascal Costanza <[EMAIL PROTECTED]> wrote: > You can ignore the #'. In Scheme this as follows: > > (define blackhole (argument) > blackhole) > > It just means that the function blackhole returns the function blackhole.
So, in other words, it's equivalent to (Y (\fa.f)) in lambda calculus, where \ is lambda, and Y is the fixed point combinator? -- Chris Smith - Lead Software Developer / Technical Trainer MindIQ Corporation -- http://mail.python.org/mailman/listinfo/python-list
