> lst = [1,2,3,4,5]
> while lst:
> lst.pop()
>
> Or even just:
>
> lst = []
Subtly different though...
>>> while lst:
... lst.pop()
...
5
4
3
2
1
>>> lst2
[]
>>> lst = [1,2,3,4,5]
>>> lst2 = lst
>>> lst = []
>>> lst2
[1, 2, 3, 4, 5]
>>> lst = [1,2,3,4,5]
>>> lst2 = lst
>>> del lst[:]
>>> lst2
[]
The original while loop changes the actual list, reassigning it
to a new list prevents other items that reference that list from
accessing the changes. As shown above, I recommend
del lst[:]
which should be as fast as python will let one do it. (maybe?
again with those timeit guys... ;)
-tkc
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