Hi,
In code 2 you only wait for tasks[6] to be complete and then your program
finish
that is why the program prints until hello 6-- and exit change it to the
last task 9 and you will see all the output.
you can use the loop.run_forever() but then your program will never quit
until you will close the loop.
That why you need the asyncio.wait(tasks)
https://python.readthedocs.io/en/stable/library/asyncio-task.html#asyncio.wait
read this
On Friday, 4 May 2018 14:44:56 UTC+3, AJAY AJITH wrote:
>
> hi, Im a beginner in asyncio. I was trying out some small scripts to bet
> the basic idea of asyncio. The below script is meant to print "hello" after
> some time period "after" is expired. But i have a strange output when i
> dont use asyncio.wait() inside run_until_complete().
>
>
> *code 1 :*
>
> async def say_hello(after):
> await asyncio.sleep(after)
> print('hello {0}'.format(after),end='--\n')
>
>
> if __name__ == '__main__':
> loop = asyncio.get_event_loop()
> a = count()
> coros = []
> tasks = []
> for i in range(10):
> #coros.append(say_hello(i))
> tasks.append(asyncio.ensure_
> future(say_hello(i)))
> tasks = asyncio.wait(tasks)
> loop.run_until_complete(tasks)
>
>
>
> *output*hello 0--
> hello 1--
> hello 2--
> hello 3--
> hello 4--
> hello 5--
> hello 6--
> hello 7--
> hello 8--
> hello 9--
>
>
>
>
> *this works as intended.code 2: * async def say_hello(after):
> await asyncio.sleep(after)
> print('hello {0}'.format(after),end='--\n')
>
>
> if __name__ == '__main__':
> loop = asyncio.get_event_loop()
> a = count()
> coros = []
> tasks = []
> for i in range(10):
> #coros.append(say_hello(i))
> tasks.append(asyncio.ensure_future(say_hello(i)))
> #tasks = asyncio.wait(tasks)
> loop.run_until_complete(tasks[6])
>
> *output*
> hello 0--
> hello 1--
> hello 2--
> hello 3--
> hello 4--
> hello 5--
> hello 6--
>
>
> *why did it give such an output?*
>
