You can use a defaultdict to order the items and then convert that back
again to a nested list:
>>> from collections import defaultdict
>>> d = defaultdict(list)
>>> for i in x:
... d[i[0]].extend(i[1:])
...
>>> d
defaultdict(<type 'list'>, {'NM100': [3, 4, 5, 6, 7, 10, 11, 12, 13],
'NM200': [15, 16, 17]})
>>> z = [ [k] + v for k,v in d.items() ]
>>> z
[['NM100', 3, 4, 5, 6, 7, 10, 11, 12, 13], ['NM200', 15, 16, 17]]
---
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On Tue, Jul 27, 2010 at 2:32 PM, Vikram K <kpguy1...@gmail.com> wrote:
> Suppose i have this nested list:
>
> >>> x
> [['NM100', 3, 4, 5, 6, 7], ['NM100', 10, 11, 12, 13], ['NM200', 15, 16,
> 17]]
> >>> for i in x:
> ... print i
> ...
> ['NM100', 3, 4, 5, 6, 7]
> ['NM100', 10, 11, 12, 13]
> ['NM200', 15, 16, 17]
> >>>
>
> how do i obtain from the above the following nested list:
>
> >>> z
> [['NM100', 3, 4, 5, 6, 7, 10, 11, 12, 13], ['NM200', 15, 16, 17]]
> >>> for i in z:
> ... print i
> ...
> ['NM100', 3, 4, 5, 6, 7, 10, 11, 12, 13]
> ['NM200', 15, 16, 17]
> >>>
>
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