Hi,
I am using EasyDialogs (AskFileForOpen) and I am not able to set the
initial open path. I found in Python help that it should be 3rd
parameter, then I tried this
filename = EasyDialogs.AskFileForOpen("title","*.*","d:\\")
but it does not work, and opens dialog in actual directory of running script.
os.chdir("d:\\") before AskFileForOpen also does not work.
Does anybody have some idea to solve this situation?
I would be grateful.
Radovan Grznarik
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