Try Exec with the file handle
On 12/6/06, Tim Roberts <[EMAIL PROTECTED]> wrote:
Wu, Huaxing (STP) wrote:
>
> Hi, all,
>
> I have some problem using os.system when a command that spawned by
> os.system itself tries to use os.system. It may be easier to explain
> with an example.
>
> Assume I have 3 python scripts. They are aa.py, bb.py and cc.py.
> File aa.py (Try to run bb.py using os.system)
> import os
> print "in", __file__
> sysCode = os.system("bb.py")
> Print "executing bb.py ", sysCode
>
> File bb.py (try to run cc.py using os.system)
> import os
> print "in", __file__
> sysCode = os.system("cc.py")
> Print "executing cc.py ", sysCode
>
> File cc.py
> import os
> print "in", __file__
>
> On command line, run "aa.py"
>
> And cc.py never get run. Is there anything wrong in the code?
>
Works for me in Windows XP, once I fixed your print/Print confusion.
What environment are you in?
C:\tmp\x>type aa.py
import os
print "in", __file__
sysCode = os.system("bb.py")
print "executing bb.py ", sysCode
C:\tmp\x>type bb.py
import os
print "in", __file__
sysCode = os.system("cc.py")
print "executing cc.py ", sysCode
C:\tmp\x>type cc.py
import os
print "in", __file__
C:\tmp\x>python aa.py
in aa.py
in C:\tmp\x\bb.py
in C:\tmp\x\cc.py
executing cc.py 0
executing bb.py 0
C:\tmp\x>
--
Tim Roberts, [EMAIL PROTECTED]
Providenza & Boekelheide, Inc.
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